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Quantitative Analysis

Study Notes and Chapters for Quantitative Analysis - Online Preparation for Bank Exams

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Quantitative Analysis requires a lot of practice and hardwork since its an analytical subject. Before becoming an expert one should understand the basics of Quantitative Analysis for Government Bank Job Exams for SBI, RBI, RRB and IBPS. This section gives you all details about the basics of Quantitative Analysis. Here you can get the Free Notes and PDF downloads for Quantitative Analysis to prepare for the Bank PO and Clerical Jobs in India. Our experts are available incase you need any kind of online help to understand any topic or any kind of doubt clearing

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Quantitative Aptitude Free-Study Notes

8. PERCENTAGE

 

A. Concept of Percentage : A fraction with its denominator as ‘100’ is called a percentage. Percentage means per hundred. So it is a fraction of the form 6/100 , 37/100, 151/100 and these fractions can be expressed as 6%, 37% and 151% respectively. By a certain percent ,we mean that many hundredths.

Thus x percent means x hundredths, written as x%.
To express x% as a fraction : We have , x% = x/100.
Thus, 20% =20/100 =1/5; 48% =48/100 =12/25, etc.
To express a/b as a percent : We have, a/b =((a/b)*100)%.

Thus, ¼ =[(1/4)*100] = 25%; 0.6 =6/10 =3/5 =[(3/5)*100]% =60%.

B. If the price of a commodity increases by R%, then the reduction in consumption so as not to increase the expenditure is
[R / (100+R))*100] %.

If the price of the commodity decreases by R%, then the increase in consumption so as to decrease the expenditure is
[(R / (100-R)*100] %.


C. Results on Population : Let the population of the town be P now and suppose it increases at the rate of R% per annum, then :
1. Population after n years = P [1+(R/100)]n.
2. Population n years ago = P / [1+(R/100)]n.


D. Results on Depreciation : Let the present value of a machine be P. Suppose it depreciates at the rate R% per annum. Then,
1. Value of the machine after n years = P [1-(R/100)]n.
2. Value of the machine n years ago = P / [1-(R/100)]n.


E. If A is R% more than B, then B is less than A by
[(R/(100+R))*100]%.

If A is R% less than B , then B is more than A by
[(R/(100-R))*100]%.

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